Question
The maximum kinetic energy of photoelectrons from a surface with work function $\phi = 2 \text{ eV}$ when light of $\lambda = 4000 \text{ Å}$ falls on it is:
$(hc = 12400 \text{ eV·Å})$
Options
- A
$1.1 \text{ eV}$
- B
$2 \text{ eV}$
- C
$3.1 \text{ eV}$
- D
$0.5 \text{ eV}$