Question
A particle moves along the $x$-axis with acceleration $a = -\omega^2 x$. If at $t = 0$, $x = A$ and $v = 0$, then $x(t)$ is:
Options
- A
$A\cos(\omega t)$
- B
$A\sin(\omega t)$
- C
$Ae^{-\omega t}$
- D
$A\cos(\omega t) + A\sin(\omega t)$
A particle moves along the $x$-axis with acceleration $a = -\omega^2 x$. If at $t = 0$, $x = A$ and $v = 0$, then $x(t)$ is:
$A\cos(\omega t)$
$A\sin(\omega t)$
$Ae^{-\omega t}$
$A\cos(\omega t) + A\sin(\omega t)$