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JEE Advanced 2025 — Chemistry Organic Chemistry
medium
mcq
2025
Question
The major product of the reaction: $\text{CH}_3\text{CH}=\text{CH}_2 + \text{HBr}$ (in presence of peroxide) is:
Options
- A
$\text{CH}_3\text{CHBr}\text{CH}_3$ (Markovnikov)
- B
$\text{CH}_3\text{CH}_2\text{CH}_2\text{Br}$ (Anti-Markovnikov)
- C
$\text{CH}_2\text{Br}\text{CH}=\text{CH}_2$
- D
$\text{CH}_3\text{CBr}=\text{CH}_2$